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 Homework Statement:
 A set of 16 party lights were purchased for the patio, 2x of 8 sets of bulbs are in parallel with each other, so if i disconnect one bulb, only half of the lights will go out. When all bulbs are functional they draw 3.2Amps from the 24.0V transformer. I need to determine the voltage across each globe, the current through each globe, the power consumed by each globe and finally, if we had a power board with a circuit breaker rated to flip at 10A, how many sets of lights could I operate before flipping the circuit breaker? Thanks :)
 Relevant Equations:

V = IR
P = IV
V = 24V
I = 3.2A
16 globes (2x 8 in parallel) (8 globes in series)
To determine the voltage I did voltage/number of globes:
24/16 = 1.5V per globe
 Not sure if this is correct or not
To determine current, I figured out using resistance formulas that the resistance for each set of 8 globes is 15 ohms
R = V/I
24/3.2 = 7.5 ohms total resistance
7.5^{1} = 2 * 15^{1}
Each set of 8 has resistance of 15 ohms.
therefore each globe has an individual resistance of 1.875 ohms, I then used I = V/R to get 0.8A per globe.
 Not sure if this is correct or not
To solve power I simply did P = IV,
1.5 x 0.8 = 1.2W
 Again, not sure if this is correct
The last one I'm stumped, no idea how I could figure it out.
Thanks in advance for people who reply :)
24/16 = 1.5V per globe
 Not sure if this is correct or not
To determine current, I figured out using resistance formulas that the resistance for each set of 8 globes is 15 ohms
R = V/I
24/3.2 = 7.5 ohms total resistance
7.5^{1} = 2 * 15^{1}
Each set of 8 has resistance of 15 ohms.
therefore each globe has an individual resistance of 1.875 ohms, I then used I = V/R to get 0.8A per globe.
 Not sure if this is correct or not
To solve power I simply did P = IV,
1.5 x 0.8 = 1.2W
 Again, not sure if this is correct
The last one I'm stumped, no idea how I could figure it out.
Thanks in advance for people who reply :)