# Simple Trajectory

First I want to know the path the shell will follow through space. It's like putting a bright light on the shell, and photographing the entire flight with the camera's shutter stuck open. When I develop the film, I see a portion of a parabola that begins at the cannon and ends where the shell hits the ground.

I start with the basic laws of motion in the x and y direction. I will assume that the projectile starts at coordinate x=0, y=0, and ignore air friction. If "v0" is the initial velocity, and "angrad" is the angle of inclination of the velocity vector (cannon barrel) from the horizontal, then the x location at any time t after firing is:

```x = v0* cos(angrad) * t                               (1)
```
and the y location at the same time is:

```y = v0 * sin(angrad) * t  -  0.5 * g * t**2           (2)
```
for our problem v0=300 meters per second (about sound speed) and g =9.807 m/s**2

I solve Equation (1) for t and get:

Now I substitute this into Equation (2) and get:

This is the equation for the light streak in our picture. and we want to locate the point other than x=0 for which y(x)=0. Setting y(x)=0 in the above equation and factoring gives:

The solution of interest is when: