One team member should open a word processor to
record the steps used in this exercise,
while the other(s) setup a SNAP session on an adjacent computer.
Start
by creating a directory for the exercise and opening a copy of the
model that you generated for exercise 2.
This is a series of three extensions to Exercise 2. The first is designed to give you a feel for the impact of number of finite volumes used in the system model, and the relative behavior of available numerical methods. This is a qualitative study of mesh size, and does not use the more rigorous approaches from lectures on error analysis and verification. The second portion of the exercise adds effects of the pipe wall on the transient, and the third part gives you experience adding power to a metal structure and extracting the heat through the fluid flow.
Part 1
Flow
and basic geometry are the same as in exercise 2. Flow is through a 10 meter section of
0.25 m diameter circular pipe. Initially, water flows into the test
section at 1 m/s with a temperature of 300K. From
Part 2
Now add a bit more reality to the problem. Model the pipe wall
with a
heat structure. The wall is Inconel 600, 0.01 m thick. Take
its
initial temperature as 300K, and assume that the outside of the pipe
wall is perfectly insulated. Place 6 evenly spaced radial temperature
nodes in the
wall, and be certain that there are a total of 100 rows of these radial
nodes, one corresponding to each fluid volume. Alter the model
properties so that the transient runs for 100 seconds.
Select the "SETS
Numerics" type that
gave the best results in the first portion of this
exercise.
Plot temperature in fluid volume 45 versus time for this calculation
and for the corresponding run without a wall model on the same axes.
Limit the time axis in this plot to 0-10 s. What causes the
differences in
fluid temperature? Plot the wall temperature (rftn) in radial
node 6
and axial node 45 (4.5 meters from the inlet). Note that metal
structures require the longest time to reach steady state.
Part
3
Assume that the pipe wall is electrically heated with power distributed
uniformly through the volume. Use your knowledge of
thermodynamics and fluid dynamics to calculate the total power required
to give a temperature at the pipe exit of 360K when a transient with
the above initial and boundary conditions is run to a steady
state. Modify your previous model to include that power and plot
temperature in the last fluid volume as a function of time for a 50
second run. If necessary adjust your power, and rerun the
calculation until the temperature in the last pipe cell is within 0.5K
of 360K.



With the metal pipe wall represented, all that remains is to supply a
power source. This is a separate component found on the Component
Navigator window. Expand the "Power Data" item, then right click
on "Power Components", and select new.

The power component has a great
deal of flexibility and a corresponding long list of possible inputs in
its properties. For this exercise only a few of the items need to
be set. As usual provide the Component Name, Description, and
Comments. For the "Power Option" select "Constant Power", and set
the "Initial Power" to the value that you calculated to produce the
required temperature rise in the liquid.

Expand the "Powered Components" item, and move your wall heat structure
from the unpowered to the powered list.

Since there is only one heat structure, you should assign its power
fraction to 1.0 and close this window.
The last thing that you normally need to do is to provide a profile (or
profiles) describing the axial distribution of the power in the heat
structure. Input here is a little confusing because of the
flexibility provided to users. You have the capability to provide
profiles at any set of times, and to interpolate between these profiles
during a transient (this is basically a table with two independent
variables). For this exercise, the power profile is flat,
and constant with time. Because of the way the time table is
handled internally, the time independence can be accomplished by
providing only one time entry for t=0.0, which already has a default
uniform distribution
Click the + to expand the Power Shape box and expand the "Power Shape
Table"
row. The axial locations for power
table entries are
already provided from the axial nodalization of the wall heat
structure. In the resulting window,
the Abscissa to Problem Time
(signal variable 1), and click the "Add Shape" button. The
"Abscissa-Coordinate Value" is just the point in time at which this
power shape is evaluated and should be set to 0.0. Because only
one profile will be entered, all times greater than zero will also use
this profile. The right column of the power shape table should
default to 1.0, to give uniform distribution of the power. The
program
will automatically normalize this distribution.

At this point you should save your project and run the problem to see
if you can get results.
The written summary of your activities, should include:
Clean up the summary of your adventures, and submit it with your plots
and answers to my questions
as Homework 6.